.BuildingSystems.HAM.Data.MaterialProperties.Thermal.Copper .BuildingSystems.HAM.Data.MaterialProperties.Thermal.Copperrecord Copper = BuildingSystems.HAM.Data.MaterialProperties.BaseClasses.MaterialThermalGeneral(id = 6, name = "Copper", lambda = 380.0, c = 383.0, rho = 8920.0);